Happy Birthday Omega!!!!! =D

[-Archmage-]

Original:    2x * (dy/dx) + y = y2 * sqrt(x-(x2*y2))
Simplified: 2x * (dy/dx) = y * sqrt(-xyy)

How good did I do?
I can't simplify it anymore.

[Omega]

Sure you can. The point is to get it down to x = ?

I saw the answer to it, but it's WAY to complex to post in plain text and these mathmatic image generating sites don't work well on the dark grey of the board.

[-Archmage-]

Ok, then how about:

x = y * sqrt(-xyy) / (dy/dx) / 2

 

[Omega]

No. The cheap way to do it would be:

x= (y * sqrt(-xyy) * (dy/dx))/x
But that's not correct. It's still incomplete.

[-Archmage-]

It's been over a year since I did algebra, and I suck at remembering things.

As far as I know you're wrong...... Maybe I should send this to my old math teacher, she could solve this in about 2 seconds.

[Omega]

It's been over a year since I did algebra, and I suck at remembering things.

As far as I know you're wrong...... Maybe I should send this to my old math teacher, she could solve this in about 2 seconds.

OMG! Did you quit math? Doesn't most maths use algebra? My math 8-20 courses have all used algebra in some ways.

[-Archmage-]

Yea, I covered all different kinds of algebra last year(advanced classes).
But I don't remember all that much of it.

Back when I was learning it, I loved it!


Dude, I don't even go to school anymore. I'm self-taught.

[xxcatmysteryxx]

I can probably figure it out but im too lazy to try; plus im in pre-algebra it teaches you the basics i think we already learned how to do most or some of that

[Gabbe]

Dude, I don't even go to school anymore. I'm self-taught. Cheesy

seriously!???!

[xxcatmysteryxx]

Dude, I don't even go to school anymore. I'm self-taught. Cheesy

seriously!???!

its true........

[Gabbe]

Dude, I don't even go to school anymore. I'm self-taught. Cheesy

seriously!???!

its true........

No way.. how are you supposed to get a job? and i mean a decent job...

[xxcatmysteryxx]

Dude, I don't even go to school anymore. I'm self-taught. Cheesy

seriously!???!

its true........

No way.. how are you supposed to get a job? and i mean a decent job...

he went to school for a little while for the job thing idk you need to pass high school to at least get a job at McDonalds and other places

[Gabbe]

how do you know all this stuff?

[xxcatmysteryxx]

how do you know all this stuff?

I'm a creeper/stalker. I have information...... for him that's classified

also my sister told me about the McDonalds thing

[Gabbe]

maybe you two are in a rela--- anyways thats crazy to drop out just like that...

[ultifd]

Well, yeah.  Still...I don't like the signs...

Dude, I don't even go to school anymore. I'm self-taught

So that is another reason why you have so much time...jk

[Gabbe]

Well, yeah.  Roll Eyes Still...I don't like the signs...

are you interested in arch too!?!?

[-Archmage-]

For a job, I'll probably become an investor.

I'll find a way, I always do......somehow......


Gabbe I've known Stephanie for a long time, you'd think I'd tell her sometime that I school myself.

She's just kidding around about stalking me.

[@kukac@]

Dude, I don't even go to school anymore. I'm self-taught. Cheesy

seriously!???!

its true........

No way.. how are you supposed to get a job? and i mean a decent job...

he went to school for a little while for the job thing idk you need to pass high school to at least get a job at McDonalds and other places

Happy birthday Omega

[Gabbe]

i didn`t know you two knew eachother before the forums...that explains a lot.


kukac have returned! can kukac solve the math?

[ultifd]

It's been solved. 
Anyways,
is tomorrow the big day? or the day after.... 

[Gabbe]

2x * (dy/dx) + y = y2 * sqrt(x-(x2*y2))

hasn`t been solved cause

X  =  ?

so ? isn`t a number yet, therefore it is not solved?

[Omega]

x=Ke^{-\frac{2\sqrt{x-x^2y^2}}{xy}}
For those of you who can read LaTeX code, that's the answer. You can use a LaTeX generator to view it.

EDIT://
Ah, found a generator. Click to see the formula image.
http://latex.codecogs.com/gif.latex?x=Ke^{-\frac{2\sqrt{x-x^2y^2}}{xy}}

x=Ke^(-(2sqrt(x-x^2^2y^2))/(xy))
For those of you who can't read LaTeX, this works too, but is kinda messier...

[Gabbe]

and im out this get WAY to complex...

[xxcatmysteryxx]

and im out this get WAY to complex...

Yes; i think he's showing off to see how smart he is because it's his birthday... lol jk. We all know you are smart. HAPPY BIRTHDAY